F(x)=(x^2-3x+6)

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Solution for F(x)=(x^2-3x+6) equation: 



(F)=(F^2-3F+6)

We move all terms to the left:

(F)-((F^2-3F+6))=0



We calculate terms in parentheses: -((F^2-3F+6)), so:

(F^2-3F+6)

We get rid of parentheses

F^2-3F+6

Back to the equation:

-(F^2-3F+6)



We get rid of parentheses

-F^2+F+3F-6=0

We add all the numbers together, and all the variables

-1F^2+4F-6=0

a = -1; b = 4; c = -6;
Δ = b2-4ac
Δ = 42-4·(-1)·(-6)
Δ = -8
Delta is less than zero, so there is no solution for the equation

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